13x^2+27x+14x=0

Solution for 13x^2+27x+14x=0 equation:

13x^2+27x+14x=0

We add all the numbers together, and all the variables

13x^2+41x=0

a = 13; b = 41; c = 0;
Δ = b2-4ac
Δ = 412-4·13·0
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-41}{2*13}=\frac{-82}{26}
=-3+2/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+41}{2*13}=\frac{0}{26}
=0
$